]> Exercise 3

Math Animated™
Mathematical Introduction for Physics and Engineering
by Samuel Dagan (Copyright © 2007-2020)

Chapter 2: Integration; Section 1: Indefinite Integrals; page 1

Definitions and Basics, Exercise 3


Question

Calculate the following integrals:

  1. tan 2 xdx
     
  2. dx tan 2 x
     
  3. dx 1 x 4
    Hint for the last case: ( 1 x 4 )=( 1+ x 2 )( 1 x 2 )

Reminder

{ cosxdx =sinx+C sinxdx =cosx+C ( 1+ tan 2 x ) dx= dx cos 2 x =tanx+C ( 1+ cot 2 x ) dx= dx sin 2 x =cotx+C } (2.1.1.14)
{ dx 1 x 2 =( or ) { ±asinx+C acosx+C dx 1+ x 2 =( or ) { +atanx+C acotx+C } (2.1.1.15)
{ dx 1+ x 2 =asinhx+C dx x 2 1 =acoshx+C dx 1 x 2 =atanhx+C( | x |<1 ) dx 1 x 2 =acothx+C( | x |>1 ) } (2.1.1.18)

Parts 1-2

Solution of question 1

  1. Among the integrals known so far the tan 2 xdx is included in (2.1.1.14): ( 1+ tan 2 x )dx =tanx+C
  2. as a consequence: tan 2 x dx=tanx dx =tanxx+C

Parts 3-5

Solution of question 2

  1. Among the integrals known so far the dx tan 2 x is not included, but 1 tanx =cotx
     
  2. and therefore (2.1.1.14) could be used: dx( 1+ cot 2 x ) = dx( 1+ 1 tan 2 x ) = 1 tanx +C
     
  3. As a consequence: dx tan 2 x = 1 tanx dx =( 1 tanx +x )+C

Parts 6-9

Solution of question 3

  1. The integral dx 1 x 4 does not appear among the known integrals,
    but according to the hint one have to look for the expressions (1+x2) and (1−x2) and luckily they are in (2.1.1.15) and (2.1.1.18).
  2. We have to seek for a possible solution of 1 1 x 4 = A 1+ x 2 + B 1 x 2
  3. Indeed we obtain A 1+ x 2 + B 1 x 2 = ( A+B )+( A+B ) x 2 1 x 4 and the requirement is fulfilled with A=B= 1 2
  4. Finally we obtain dx 1 x 4 = 1 2 dx 1+ x 2 + 1 2 dx 1 x 2 = = atanx 2 +{ 1 2 atanhxfor( | x |<1 ) 1 2 acothxfor( | x |>1 ) }+C

Score

By questions:

Question 1 gives credit of 2 points.
Question 2 gives credit of 3 points.
Question 3 gives credit of 5 points.

By parts:

Parts 1,2,3,4,5,6,8,9 are worth 1 point each.
Part 7 is worth 2 points.